Why Can't a Linear Equation Have Two Solutions?

A linear equation in one variable cannot have two distinct solutions. Let's explore why.

Consider the linear equation:

$$ ax = b $$

where \( a \) and \( b \) are numbers and \( x \) is the unknown variable.

The coefficients \( a \) and \( b \) can either be zero or non-zero.

Let's analyze each case individually.

1] Case \( a \ne 0 \)

If \( a \) is not zero, we can solve the equation by isolating \( x \):

$$ x = \frac{b}{a} $$

In this scenario, the equation has a unique solution, given by \( x = \frac{b}{a} \).

2] Case \( a = 0 \)

In this situation, we need to consider two sub-cases:

  • \( b \ne 0 \)
    If \( a = 0 \) and \( b \ne 0 \), the equation becomes $$ 0 \cdot x = b $$. This is a contradiction because 0 cannot equal a non-zero number. Therefore, there are no solutions.
  • \( b = 0 \)
    If \( a = 0 \) and \( b = 0 \), the equation becomes: $$ 0 \cdot x = 0 $$. This is an identity true for any value of \( x \). In this case, the equation has infinite solutions.

Conclusion

In conclusion, from our analysis, we can state that:

  • If \( a \ne 0 \), the equation has one unique solution.
  • If \( a = 0 \) and \( b \ne 0 \), the equation has no solutions.
  • If \( a = 0 \) and \( b = 0 \), the equation has infinite solutions.

Therefore, a linear equation in one variable can never have exactly two distinct solutions.




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