Why Can't a Linear Equation Have Two Solutions?
A linear equation in one variable cannot have two distinct solutions. Let's explore why.
Consider the linear equation:
$$ ax = b $$
where \( a \) and \( b \) are numbers and \( x \) is the unknown variable.
The coefficients \( a \) and \( b \) can either be zero or non-zero.
Let's analyze each case individually.
1] Case \( a \ne 0 \)
If \( a \) is not zero, we can solve the equation by isolating \( x \):
$$ x = \frac{b}{a} $$
In this scenario, the equation has a unique solution, given by \( x = \frac{b}{a} \).
2] Case \( a = 0 \)
In this situation, we need to consider two sub-cases:
- \( b \ne 0 \)
If \( a = 0 \) and \( b \ne 0 \), the equation becomes $$ 0 \cdot x = b $$. This is a contradiction because 0 cannot equal a non-zero number. Therefore, there are no solutions. - \( b = 0 \)
If \( a = 0 \) and \( b = 0 \), the equation becomes: $$ 0 \cdot x = 0 $$. This is an identity true for any value of \( x \). In this case, the equation has infinite solutions.
Conclusion
In conclusion, from our analysis, we can state that:
- If \( a \ne 0 \), the equation has one unique solution.
- If \( a = 0 \) and \( b \ne 0 \), the equation has no solutions.
- If \( a = 0 \) and \( b = 0 \), the equation has infinite solutions.
Therefore, a linear equation in one variable can never have exactly two distinct solutions.