Converting a cell array into a structure in Octave

In this lesson, I will explain how to convert a cell array into a structure using the cell2struct() function in Octave.

Let me give you a practical example.

Create an array of cells in the variable A.

>> A={"Math", "Latin", "Science"; 97, 60, 78};

This cell array is composed of a table with two rows and three columns.

Math	Latin	Science
97	60	78

To convert it into a structure, use the function cell2struct()

Type B=cell2struct(A, {'exam', 'grade'})

>> B=cell2struct(A, {'exam', 'grade'})

The function has two parameters:

• The first parameter is the variable A, which contains the array of cells.
• The second parameter is the list of fields in the structure, enclosed in curly braces, i.e., {'lesson', 'grade'}.

A structure of array with the data from the cell array is created in the variable B.

For example, if you enter B(1,1,:)(:), you will obtain the data from the first column.

>> B(1,1,:)(:)
ans =

scalar structure containing the fields:

exam = Math
grade = 97

If you enter B(2,1,:)(:), you will obtain the data from the second column.

>> B(2,1,:)(:)
ans =

scalar structure containing the fields:

exam = Latin
grade = 60

If you enter B(3,1,:)(:), you will obtain the data from the third column.

>> B(3,1,:)(:)
ans =

scalar structure containing the fields:

exam = Science
grade = 78